Anualidades Anticipadas

$$M=R\frac{(1+i)^n-1}{i}(1+i)$$

$$M=R\left[\frac{(1+i)^{n+1}-1}{i}-1\right]$$

$$C=R\left[1+\frac{1-(1+i)^{-n+1}}{i}\right]$$

$$n=1-\frac{log\left[1+i-(\frac{Ci}{R})\right]}{log(1+i)}$$