Categoria: formulae.app / Matemáticas / Matemáticas Discretas / Trigonométricas Inversas
$$\frac{d(arc \: sen \: V)}{dx}= \frac{\frac{d(v)}{dx}}{\sqrt{1-v^2}}$$
$$\frac{d(arc \: cos \: V)}{dx}= - \frac{\frac{d(v)}{dx}}{\sqrt{1-v^2}}$$
$$\frac{d(arc \: Tg \: V)}{dx}= \frac{\frac{d(u)}{dx}}{1+v^2}$$
$$\frac{d(arc \: ctan \: V)}{dx}= - \frac{\frac{d(v)}{dx}}{1+v^2}$$
$$\frac{d(arc \: sec \: V)}{dx}= \frac{\frac{d(v)}{dx}}{^v\sqrt{v^2-1}}$$
$$\frac{d(arc \: csc \: V)}{dx}= - \frac{\frac{d(v)}{dx}}{^v\sqrt{v^2-1}}$$