Categoria: formulae.app / Matemáticas / Cálculo Diferencial / Derivada de Funciones Trigonométricas Inversas
$$f(x) = arc\:sin(u) \hspace{3em} f'(x) = \frac{u'}{\sqrt{1-u^2}}$$
$$f(x) = arc\:cos(u) \hspace{3em} f'(x) = \frac{u'}{\sqrt{1-u^2}}$$
$$f(x) = arc\:tan(u) \hspace{3em} f'(x) = \frac{u'}{\sqrt{1+u^2}}$$
$$f(x) = arc\:cot(u) \hspace{3em} f'(x) = \frac{u'}{\sqrt{1+u^2}}$$
$$f(x) = arc\:sec(u) \hspace{3em} f'(x) = \frac{u'}{u \cdot \sqrt{u^2 - 1}}$$
$$f(x) = arc\:csc(u) \hspace{3em} f'(x) = \frac{u'}{u \cdot \sqrt{u^2 - 1}}$$